RiSks. Posted May 9, 2008 Report Share Posted May 9, 2008 1. If f(x) = -x^3 + x +1/x, then f'(-1) = 2. The graph of y= 3x^4 - 16x^3 + 24x^2 + 48 is concave down for (Can't use calculator) 3. 1/2 (Integral Sign) e^t/2 dt = Link to comment Share on other sites More sharing options...
Harry Posted May 9, 2008 Report Share Posted May 9, 2008 1. f(x) = -x^3+x+(1/x) f'(x)= -3x^2+1-1 (1/x = 1(x)^-1) f'(-1)= -3(-1)^2+1-1 f'(-1)= -3 Link to comment Share on other sites More sharing options...
foxshox Posted May 10, 2008 Report Share Posted May 10, 2008 2. Find y'' and then find the critical points. Then test points in each range, and find out where the y'' is negative. Then that's where it is concave down for. 3. e^(t/2) Link to comment Share on other sites More sharing options...
RoundBear Posted May 15, 2008 Report Share Posted May 15, 2008 foxshox so smaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaart in math. it's my worse subject/areaa.aa Link to comment Share on other sites More sharing options...
foxshox Posted May 15, 2008 Report Share Posted May 15, 2008 foxshox so smaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaart in math. it's my worse subject/areaa.aa man shit, if i could be doing shit like this, i would be way more chill.. fuck engineering Link to comment Share on other sites More sharing options...
RoundBear Posted May 27, 2008 Report Share Posted May 27, 2008 I wish i have your math brain foxshox. Link to comment Share on other sites More sharing options...
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